How do you simplify (sinxcosx)/(1-sin^2x)sinxcosx1sin2x?

I got cotxcotx as an answer... don't know if it is right though...

2 Answers
Nov 27, 2017

(sinx*cosx)/(1-sin^2x)==tanxsinxcosx1sin2x==tanx

Explanation:

(sinx*cosx)/(1-sin^2x)=(sinx*cosx)/cos^2x=sinx/cosx=tanxsinxcosx1sin2x=sinxcosxcos2x=sinxcosx=tanx

Nov 27, 2017

See the answer below...

Explanation:

(sinxcosx)/(1-sin^2x)=(sinxcosx)/cos^2xsinxcosx1sin2x=sinxcosxcos2x[BECAUSE color(red)(sin^2x+cos^2x=1sin2x+cos2x=1]
color(white)(mmmmfG)=(sinxcancelcosx)/(cosxcdotcancelcosx)=color(red)(tanx

So the answer is color(brown)(tanx

Hope it helps...
Thank you...