How do you simplify $(sinxcosx)/(1-sin^2x)$ ?

Question

6022 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-03T21:48:32

The answer is $\tan(x)$

By the fundamental formula $sin^2(x)+cos^2(x)=1$ , you have that $1-\sin^2(x)=\cos^2(x)$ . So, your fraction becomes

${\sin(x)\cos(x)}/{\cos^2(x)}$ , and you can simplify a cosine to obtain $\sin(x)/\cos(x)$ , which is exactly $\tan(x)$ .

How do you simplify (sinxcosx)/(1-sin^2x)(sinxcosx)/(1-sin^2x)?