How do you simplify, $sin (θ) + cos (θ) tan (θ)$ $sin(theta)+cos(theta)tan(theta)$ ?

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How do you simplify, $sin (θ) + cos (θ) tan (θ)$ $sin(theta)+cos(theta)tan(theta)$ ?

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Answer 1 · 2015-04-16T13:24:15

Just use the fact that $tan (θ) = \frac{sin (θ)}{cos (θ)}$ $tan(theta)=sin(theta)/cos(theta)$ to write $sin (θ) + cos (θ) tan (θ) = sin (θ) + cos (θ) \cdot \frac{sin (θ)}{cos (θ)}$ $sin(theta)+cos(theta)tan(theta)=sin(theta)+cos(theta)\cdot sin(theta)/cos(theta)$ and then cancel the $cos (θ)$ $cos(theta)$ 's to say $sin (θ) + cos (θ) tan (θ) = 2 sin (θ)$ $sin(theta)+cos(theta)tan(theta)=2sin(theta)$ .

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How do you simplify, $sin (θ) + cos (θ) tan (θ)$ $sin(theta)+cos(theta)tan(theta)$ ?

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How do you simplify, sin(θ)+cos(θ)tan(θ)sin(theta)+cos(theta)tan(theta)?

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How do you simplify, $sin (θ) + cos (θ) tan (θ)$ $sin(theta)+cos(theta)tan(theta)$ ?