How do you simplify $(sec^2(x)−1)/(tan(x)sin(x))$ ?

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Answer 1 · 2015-08-05T00:37:03

Simplify: $(sec^2 - 1)/(tan x.sin x)$

Ans: $1/cos x$

Use trig identity: $sec^2 x = 1 + tan^2 x$

$(sec^2 - 1)/(tan x.sin x) = tan^2 x/(tan x.sin x) =$

$= (sin x)/(sin x.cos x) = 1/cos x$

How do you simplify (sec^2(x)−1)/(tan(x)sin(x))(sec^2(x)−1)/(tan(x)sin(x))?