How do you simplify (root4(x^3)*root4(x^5))^(-2)?

1 Answer
Aug 28, 2017

See a solution process below:

Explanation:

First, we can use this rule to combine the radicals within the parenthesis:

root(n)(color(red)(a)) * root(n)(color(blue)(b)) = root(n)(color(red)(a) * color(blue)(b))

(root(4)(color(red)(x^3)) * root(4)(color(blue)(x^5)))^-2 = (root(4)(color(red)(x^3) * color(blue)(x^5)))^-2

Next, use this rule for exponents to combine the terms within the radical:

x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a) + color(blue)(b))

(root(4)(color(red)(x^3) * color(blue)(x^5)))^-2 = (root(4)(x^(color(red)(3)+color(blue)(5))))^-2 = (root(4)(x^8))^-2

Then, we can use this rule to rewrite the radical into an exponent:

root(color(red)(n))(x) = x^(1/color(red)(n))

(root(color(red)(4))(x^8))^-2 = ((x^8)^(1/color(red)(4)))^-2

Next, we can use this rule to simplify the inner exponents:

(x^color(red)(a))^color(blue)(b) = x^(color(red)(a) xx color(blue)(b))

((x^color(red)(8))^color(blue)(1/4))^-2 = (x^(color(red)(8) xx color(blue)(1/4)))^-2 = (x^2)^-2

We can use the same rule to reduce the outer exponents:

(x^color(red)(2))^color(blue)(-2) = x^(color(red)(2) xx color(blue)(-2)) = x^-4

We can now use this rule to eliminate the negative exponent:

x^color(red)(a) = 1/x^color(red)(-a)

x^color(red)(-4) = 1/x^color(red)(- -4) = 1/x^4