How do you simplify root4(16) *root4(128)? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Lovecraft Oct 2, 2015 root(4)(16)*root(4)(128) = 4root(4)(2^(3)) Explanation: 2*2*2*2 =16 = 2^4 16*2*2*2 = 128 = 2^(4+3) = 2^7 root(4)(16)*root(4)(128) = root(4)(2^4)*root(4)(2^(4+3)) root(4)(16)*root(4)(128) = 2*2*root(4)(2^(3)) root(4)(16)*root(4)(128) = 4root(4)(2^(3)) Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))? See all questions in Multiplication and Division of Radicals Impact of this question 1447 views around the world You can reuse this answer Creative Commons License