How do you simplify $\sqrt[4]{11} \cdot \sqrt[4]{10}$ $root4(11)*root4(10)$ ?

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How do you simplify $\sqrt[4]{11} \cdot \sqrt[4]{10}$ $root4(11)*root4(10)$ ?

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Answer 1 · 2016-04-25T11:25:08

$\sqrt[4]{11} \cdot \sqrt[4]{10} = \sqrt[4]{11 \cdot 10} = \sqrt[4]{110}$ $root4(11)*root4(10)=root4(11*10)=root4(110)$

Explanation:

The given is to simplify the product of two radicals. Since the two radicals are of the same index number, the radicands (the number inside the radical sign) may be multiplied.

$\sqrt[4]{11} \cdot \sqrt[4]{10} = \sqrt[4]{11 \cdot 10} = \sqrt[4]{110}$ $root4(11)*root4(10)=root4(11*10)=root4(110)$

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How do you simplify $\sqrt[4]{11} \cdot \sqrt[4]{10}$ $root4(11)*root4(10)$ ?

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How do you simplify root4(11)*root4(10)4√11⋅4√10root4(11)*root4(10)?

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How do you simplify $\sqrt[4]{11} \cdot \sqrt[4]{10}$ $root4(11)*root4(10)$ ?