How do you simplify (root3(9)*root3(6))/(root6(2)*root6(2))?

1 Answer
Carlo Maximo
May 11, 2017

3.

Explanation:

root(3)9 = 3^(1/3)*3^(1/3)
root(3)6 = 2^(1/3)*3^(1/3)
root(6)2 = 2^(1/6)

Now you have (3^(1/3)*3^(1/3)*2^(1/3)*3^(1/3))/(2^(1/6)*2^(1/6)), right?
By Laws of Exponents, you could combine those 3^(1/3) and 2^(1/6) and add their bases.

Now you have 3*2^(1/3)/2^(1/3). Cancelling the fraction part, you'll get 3. :)

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