How do you simplify #root3(3 )*root3(9)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Tony B May 31, 2016 :#" "root(3)(3)xxroot(3)(9)=3# Explanation: Given:#" "root(3)(3)xxroot(3)(9)# Note that #root(3)(9)=root(3)(3)xxroot(3)(3)# So we end up with #" "root(3)(3)xxroot(3)(3)xxroot(3)(3)# #(root(3)(3))^3 = 3# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1259 views around the world You can reuse this answer Creative Commons License