How do you simplify #(m^-3)(-2m^-5)(-m^6)#?

First start by moving the ( #m^-3#) and (#m^-5#) to the denominator in order to make the exponents positive. By doing this, you should get #(((-m^6)(-2))/((m^3)(m^5)))#.

Now you can multiply the two terms in the numerator. You do so in two steps:
1. multiply the coefficients #(-1)(-2)# and
2. keep the #m^6#
This should give you the term #-2m^6#. The whole fraction should look like #((2m^6)/((m^3)(m^5)))#.

Now you can multiply the two terms in the denominator. You do so in three steps:
1. multiply the coefficients #(1)(1)#,
2. keep the base #(m)#, and
3. add the exponents #3+5#.
This is based off the rule #x^a * x^b = x^(a+b)#. This should give you the term #m^8#. The whole fraction should look like #((2m^6)/(m^8))#.

Now you can divide the two terms. You do so in three steps:
1. divide the coefficients #2//1#,
2. keep the base #(m)#, and
3. subtract the exponents #6-8#.
This is based off of the rule #x^a // x^b = x^(a-b)#. This should give you the term #m^-2#.

Once again, to make the exponent positive, you have to move it to the denominator. this should give you #(2/(m^2))#.

Hope this helped!! :)