How do you simplify ${(m^{2} p^{5})}^{3}$ $(m^2p^5)^3$ ?

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How do you simplify ${(m^{2} p^{5})}^{3}$ $(m^2p^5)^3$ ?

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Answer 1 · 2017-10-22T20:03:00

$m^{6} p^{15}$ $m^6p^15$

Explanation:

$The teaching bit$ $color(blue)("The teaching bit")$

By example suppose we had the variable $a$ $a$

This may be written as $a^{1}$ $a^1$

Now compare to $a \times a \times a = a^{3} = a^{1 + 1 + 1}$ $a xx a xx a=a^3 =a^(1+1+1)$

So if we had ${(a^{2})}^{3}$ $(a^2)^3$ this would be the same as $a^{2 \times 3} = a^{6}$ $a^(2xx3)=a^6$

If you have doubts! : $2^{2} \times 2^{2} = 4 \times 4 = 16 = 2^{2 \times 2} = 16$ $2^2xx2^2 = 4xx4=16 = 2^(2xx2)=16$
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$Answering the question$ $color(blue)("Answering the question")$

Using the above approach we have:

$(m^{2 \times 3}) \times (p^{5 \times 3})$ $(m^(2xx3))xx(p^(5xx3))$

$m^{6} p^{15}$ $m^6p^15$

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How do you simplify ${(m^{2} p^{5})}^{3}$ $(m^2p^5)^3$ ?

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How do you simplify ${(m^{2} p^{5})}^{3}$ $(m^2p^5)^3$ ?