How do you simplify # log10^9 + 10^log5#?

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Answer 1 · 2016-07-21T14:54:39

I found #14# (supposing base #10# for the logs).

Supposing the base of the logs being #10# we see that:

#log10^9=9#

and:

#10^(log5)=5#

both derive from the definition of log (specifically in base #10#):
#log_10x=a ->x=10^a#

So basically you expression becomes:
#log10^9+10^(log5)=9+5=14#

If the base is not #10# then it depends...