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How do you simplify #log_x sqrt3 = ¼#?

1 Answer

Mar 22, 2016

#x=9#

Explanation:

#log_x sqrt3 = 1/4#
#x^(1/4) = sqrt3#-> use property #y=log_bx iff b^y=x#
#(x^(1/4))^4=(3^(1/2))^(4#
#x^(4/4) = 3^(4/2)#
#x^1=3^2#
#x=9#

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