How do you simplify #i^43#? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer Trevor Ryan. Jan 11, 2016 #-i# Explanation: We use the fact that #i^2=-1# to rewrite the expression and simplify : #i^43=i^42*i# #=(i^2)^21*i# #=(-1)^21*i# #=-i# Answer link Related questions How do I use DeMoivre's theorem to find #(1+i)^5#? How do I use DeMoivre's theorem to find #(1-i)^10#? How do I use DeMoivre's theorem to find #(2+2i)^6#? What is #i^2#? What is #i^3#? What is #i^4#? How do I find the value of a given power of #i#? How do I find the #n#th power of a complex number? How do I find the negative power of a complex number? Write the complex number #i^17# in standard form? See all questions in Powers of Complex Numbers Impact of this question 15659 views around the world You can reuse this answer Creative Commons License