How do you simplify and write #(4w^-6x^2)^2# with positive exponents?

1 Answer
ProfLayton
Apr 16, 2016

First of all, let's remove that big squared symbol around the whole equation. Note: You will need to know two things, #(ab)^n=a^n*b^n#, and #(a^m)^n=a^(mn)#

#(4*w^-6*x^2)^2 = 4^2*w^(-6*2)*x^(2*2)#
#= 16*w^(-12)*x^(4)#

But the question asks for all exponents (those smaller, higher numbers) to be positive. For this we need another piece of knowledge: #a^-n = 1/a^n#

#=(16*w^4)/x^12#

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