How do you simplify and write #(2.5 times 10^-3) + (4.6 times 10^-3)# in standard notation?

1 Answer
Dec 24, 2016

#0.0071#

Explanation:

In this problem the standard term is #color(red)(10^-3)#.

We can factor this term to simplify the problem:

#(2.5 xx color(red)(10^-3)) + (4.6 xx color(red)(10^-3)) -> (2.5 + 4.6) xx color(red)(10^-3) ->#

#7.1 xx color(red)(10^-3)#

Because the exponent for the 10's term is negative we must move the decimal point 3 places to the left to write this in standard notation:

#7.1 xx color(red)(10^-3) -> 0.0071#