How do you simplify #abs(-2 - 6i)#? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer Konstantinos Michailidis Jan 17, 2016 Supposing that #abs# is the magnitude of the complex number we have that #abs(-2 - 6i)=sqrt((-2)^2+(-6)^2)=sqrt40=2sqrt10# Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 1240 views around the world You can reuse this answer Creative Commons License