How do you simplify #(8sqrt3)/sqrt6#?

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Answer 1 · 2018-03-22T01:13:54

#4sqrt2#

First we need to rationalize the denominator (no radicals can be in a denominator)

#(8sqrt3)/sqrt6 rarr# Multiply the numerator and denominator by #sqrt6# to get rid of the radical

#(8sqrt18)/6#

#(8sqrt9*sqrt2)/6 rarr# 9 is a perfect square

#(8*3*sqrt2)/6#

#(24sqrt2)/6 rarr# 24 is divisible by 6

#4sqrt2#