How do you simplify $(8sqrt2)/(2sqrt8)$ ?

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Answer 1 · 2018-03-19T00:21:47

$=>+-2$

We can't factor out a perfect square out of the numerator, so it'll remain the same. Let's see what we can do with the denominator.

We can factor $sqrt8$ into $sqrt2*sqrt4$ . Thus we have:

$(8cancelsqrt2)/(2cancelsqrt2*sqrt4)$

$sqrt2$ obviously cancels with itself, and we get:

$8/(2sqrt4)$

Which can be simplified to

$8/(2*+-2)$

$=>8/(+-4)$

$=>+-2$

How do you simplify (8sqrt2)/(2sqrt8)(8sqrt2)/(2sqrt8)?