How do you simplify $((8b^4)/(2c^9))^3$ ?

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Answer 1 · 2016-04-12T00:14:25

$((8b^4)/(2c^9))^3$ can be simplified to $(64b^12)/c^27$

First, solve what you can inside the parentheses, then start using the other exponentiation:

$((8b^4)/(2c^9))^3$ but $8/2 = 4/1$ so

$((8b^4)/(2c^9))^3 = ((4b^4)/(c^9))^3$ and then apply the exponentiation

$((4b^4)/(c^9))^3 = ((4^(1*3)b^(4*3))/c^(9*3))$
$4^3 = 64$ , $1*3 = 3$ , $4*3=12$ and $9*3 = 27$ so
$((8b^4)/(2c^9))^3 = (64b^12)/c^27$

How do you simplify ((8b^4)/(2c^9))^3 ((8b^4)/(2c^9))^3?