How do you simplify $(8 + \sqrt{4}) ((- 2 + \sqrt{4})$ $(8+sqrt4)((-2+sqrt4)$ ?

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How do you simplify $(8 + \sqrt{4}) ((- 2 + \sqrt{4})$ $(8+sqrt4)((-2+sqrt4)$ ?

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Answer 1 · 2018-06-25T06:17:07

$= 0, - 24$ $= 0, -24$

Explanation:

$(8 + \sqrt{4}) \cdot (- 2 + \sqrt{4})$ $(8 + sqrt4 ) * (-2 + sqrt4)$

$\Rightarrow - 16 - 2 \sqrt{4} + 8 \sqrt{4} + 4, removing brackets and multiplying$ $=> -16 - 2sqrt4 + 8 sqrt4 + 4, " removing brackets and multiplying"$

$\Rightarrow 6 \sqrt{4} - 12 = \pm 12 - 12 = 0, - 24$ $=> 6sqrt 4 - 12 = +- 12 - 12 = 0, -24$

Answer 2 · 2018-06-25T06:21:16

$- 12 + 6 \sqrt{4}$ $-12+6sqrt4$

Explanation:

1.Multiply

$8 \cdot - 2 + 8 \cdot \sqrt{4} + (- 2) \cdot \sqrt{4} + {(\sqrt{4})}^{2}$ $8*-2+8*sqrt4+(-2)*sqrt4+(sqrt4)^2$

Simplify

$- 16 + 4 + 8 \sqrt{4} - 2 \sqrt{4}$ $-16+4+8sqrt(4)-2sqrt(4)$

Collect like terms

$- 12 + 6 \sqrt{4}$ $-12+6sqrt4$

$- 12 \pm 12$ $-12+-12$

$0, - 24$ $0,-24$

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How do you simplify $(8 + \sqrt{4}) ((- 2 + \sqrt{4})$ $(8+sqrt4)((-2+sqrt4)$ ?

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How do you simplify $(8 + \sqrt{4}) ((- 2 + \sqrt{4})$ $(8+sqrt4)((-2+sqrt4)$ ?