How do you simplify #8/sqrt3#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer searchresults Sep 1, 2016 #8sqrt3/3# Explanation: You can't have a radical in the denominator, so multiply #sqrt3# by #sqrt3# to make 3. If you multiply the denominator by something you must multiply the numerator by it as well, which leaves you with #8sqrt3/3#. Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 6871 views around the world You can reuse this answer Creative Commons License