How do you simplify $\frac{8 + \sqrt{6}}{\sqrt{2}}$ $( 8 + sqrt 6) /sqrt 2$ ?

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Answer 1 · 2016-03-26T05:37:39

$4 \sqrt{2} + \sqrt{3}$ $4sqrt2+sqrt3$

$\frac{8 + \sqrt{6}}{\sqrt{2}}$ $(8+sqrt6)/sqrt2$

$\frac{8 + \sqrt{6}}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}$ $(8+sqrt6)/sqrt2 xx sqrt2/sqrt2$

$\frac{\sqrt{2} (8 + \sqrt{6})}{2}$ $[sqrt2(8+sqrt6)]/2$

$\frac{8 \sqrt{2} + \sqrt{12}}{2}$ $(8sqrt2+sqrt12)/2$

$\frac{8 \sqrt{2} + \sqrt{4 \times 3}}{2}$ $(8sqrt2+sqrt(4xx3))/2$

$\frac{8 \sqrt{2} + 2 \sqrt{3}}{2}$ $(8sqrt2+2sqrt3)/2$

$\frac{2 (4 \sqrt{2} + \sqrt{3})}{2}$ $[2(4sqrt2+sqrt3)]/2$

$4 \sqrt{2} + \sqrt{3}$ $4sqrt2+sqrt3$

How do you simplify 8+√6√2( 8 + sqrt 6) /sqrt 2?