How do you simplify #8/sqrt 10#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Leland Adriano Alejandro Feb 9, 2016 #8/sqrt10=(4sqrt10)/5# Explanation: #8/sqrt10=8/sqrt10*sqrt10/sqrt10=(8sqrt10)/10# continue #(8sqrt10)/10=(2*4*sqrt10)/(2*5)=(cancel2*4*sqrt10)/(cancel2*5)# so that #8/sqrt10=(4sqrt10)/5# the simplest Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 6800 views around the world You can reuse this answer Creative Commons License