How do you simplify #8(4+x)^2#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Sonnhard Jul 6, 2018 #128+64x+8x^2# Explanation: We are using that #(a+b)^2=a^2+2ab+b^2# so we get #8(16+8x+x^2)# multiplying out #128+64x+8x^2# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1177 views around the world You can reuse this answer Creative Commons License