How do you simplify #(7sqrt6+3sqrt7)(8sqrt6-9sqrt7)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Kalyanam S. May 20, 2018 #color(crimson)(=> 3 (49 - 13 sqrt42)# Explanation: #(7sqrt6 +.3 sqrt7) (8sqrt6 - 9sqrt7)# #=> 56*6 + 24 sqrt42 - 63 sqrt42 - 27*7# #=> 336 - 39 sqrt42 - 189# #=> 147 - 39 sqrt42# #color(crimson)(=> 3 (49 - 13 sqrt42)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1312 views around the world You can reuse this answer Creative Commons License