How do you simplify $7 \sqrt{2} \cdot 4 \sqrt{6}$ $7sqrt2 · 4sqrt6$ ?

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Answer 1 · 2016-09-18T19:38:01

$56 \sqrt{3}$ $56 sqrt(3)$

We have: $7 \sqrt{2} \cdot 4 \sqrt{6}$ $7 sqrt(2) cdot 4 sqrt(6)$

Let's express $\sqrt{6}$ $sqrt(6)$ as $\sqrt{2} \cdot \sqrt{3}$ $sqrt(2) cdot sqrt(3)$ :

$= 7 \cdot \sqrt{2} \cdot 4 \cdot \sqrt{2} \cdot \sqrt{3}$ $= 7 cdot sqrt(2) cdot 4 cdot sqrt(2) cdot sqrt(3)$

$= 7 \cdot 2 \cdot 4 \cdot \sqrt{3}$ $= 7 cdot 2 cdot 4 cdot sqrt(3)$

$= 56 \sqrt{3}$ $= 56 sqrt(3)$

How do you simplify 7√2⋅4√6 7sqrt2 · 4sqrt6?