How do you simplify #7/(3+ sqrt7)#?

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Answer 1 · 2016-03-14T17:58:09

See the explanation

Using #(a^2-b^2)=(a+b)(a-b)#

Multiply by 1 but in the form of #1=(3-sqrt(7))/(3-sqrt(7))#

#7/(3+sqrt(7))xx(3-sqrt(7))/(3-sqrt(7))#

# = (7(3-sqrt(7)))/(3^2-7)#

#(7(3-sqrt(7)))/(9-7)#

I will let you finish this off

Hope it helps!