How do you simplify #(6sqrt 18) / (4 sqrt 8)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Sep 17, 2015 #(6sqrt 18) / (4 sqrt 8) = color(green)( 9 / 4 = 2.25# Explanation: #(6sqrt 18) / (4 sqrt 8) = (3*cancel(2)*sqrt(3^2*2))/(2*cancel(2)*sqrt(2^2*2))# We know that #color(blue)(sqrt(a*b) = sqrta*sqrtb# #= (3*sqrt(3^2)*cancel(sqrt2))/(2*sqrt(2^2)*cancel(sqrt2))# # = (3*3)/(2*2)# # =color(green)( 9 / 4 = 2.25# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1378 views around the world You can reuse this answer Creative Commons License