How do you simplify #(6 - x ^2)^2#?

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Answer 1 · 2017-06-29T13:17:22

See a solution process below:

This is a special form of a quadratic where:

#(a - b)^2 = a^2 - 2ab + b^2#

Substituting:

#6# for #a#

#x^2# for #b# gives:

#(6 - b)^2 = 6^2 - (2 * 6 * x^2) + (x^2)^2 =#

#36 - 12x^2 + x^4#

Or, in standard polynomial form:

#x^4 - 12x^2 + 36#