How do you simplify #6/(5t^2)-2/(3t)#?

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Answer 1 · 2017-04-26T17:59:49

See the solution process below:

To add or subtract fractions, each fraction must be over a common denominator. For this problem the common denominator is:

#15t^2#

We need to first multiply each fraction by the appropriate form of #1# to put each fraction over this common denominator:

#6/(5t^2) - 2/(3t) => (3/3 xx 6/(5t^2)) - ((5t)/(5t) xx 2/(3t)) => #

#18/(15t^2) - (10t)/(15t^2)#

We can now subtract the numerators over the common denominator:

#18/(15t^2) - (10t)/(15t^2) => (18 - 10t)/(15t^2)#