How do you simplify #-6 +(-2sqrt3)/ 12#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Harish Chandra Rajpoot Jul 5, 2018 #-{6\sqrt3+1}/{2\sqrt3 }# Explanation: #-6+{-2\sqrt3}/12# #=-6-{2\sqrt3}/{2^2\cdot3 }# #=-6-{1}/{2\sqrt3 }# #={-6\sqrt3-1}/{2\sqrt3 }# #=-{6\sqrt3+1}/{2\sqrt3 }# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1268 views around the world You can reuse this answer Creative Commons License