How do you simplify #(5sqrtx+2)(2sqrtx-1)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Shwetank Mauria Aug 13, 2016 #(5sqrtx+2)(2sqrtx-1)=10x-sqrtx-2# Explanation: #(5sqrtx+2)(2sqrtx-1)# = #5sqrtx×(2sqrtx-1)+2×(2sqrtx-1)# Now as #sqrtx×sqrtx=x# above can be multiplied and expanded to appear as #10x-5sqrtx+4sqrtx-2# = #10x-sqrtx-2# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 849 views around the world You can reuse this answer Creative Commons License