How do you simplify $5 \sqrt{3} \cdot 8 \sqrt{2}$ $5sqrt3 * 8sqrt2$ ?

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Answer 1 · 2015-09-13T00:06:03

$40 \sqrt{6}$ $40sqrt6$

Multiply the roots with the roots
and the integers with integers

$\sqrt{3}$ $sqrt3$ and $\sqrt{2}$ $sqrt2$ are the roots
$5$ $5$ and $8$ $8$ are the integers

$5 \sqrt{3} \cdot 8 \sqrt{2}$ $5sqrt(3)*8sqrt2" "$ is the same as $5 \cdot 8 \cdot \sqrt{3} \cdot \sqrt{2}$ $" "5*8*sqrt(3)*sqrt(2)$

$\to 5 \cdot 8 = 40$ $rarr5*8=40$

$\to \sqrt{3} \cdot \sqrt{2} = \sqrt{3 \cdot 2} = \sqrt{6}$ $rarrsqrt(3)*sqrt(2)=sqrt(3*2)=sqrt(6)$

Hence, $5 \cdot 8 \cdot \sqrt{3} \cdot \sqrt{2} = 40 \sqrt{6}$ $5*8*sqrt(3)*sqrt(2)=color(blue)(40sqrt6)$

How do you simplify 5sqrt3 * 8sqrt25√3⋅8√25sqrt3 * 8sqrt2?