How do you simplify #5sqrt(42x)(4+4sqrt(7x))#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Mark D. May 23, 2018 #20sqrt(7x)(sqrt6+1)# Explanation: #20sqrt(42x)+20sqrt(7x)# #20(sqrt(42x)+sqrt(7x))# #20[sqrt(7x)(sqrt6+1)]# #20sqrt(7x)(sqrt6+1)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1178 views around the world You can reuse this answer Creative Commons License