How do you simplify $(5cosphi)/sin^2phi*(sin^2phi-sinphicosphi)/(sin^2phi-cos^2phi)$ ?

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Answer 1 · 2016-09-19T17:02:20

$(5 cotphi)/(sinphi+cosphi)$

$(5cosphi)/sin^2phi*(sin^2phi-sinphicosphi)/(sin^2phi-cos^2phi)=$

$(5cosphi)/sin^2phi*(sin phi(sinphi-cosphi))/((sinphi-cosphi) (sinphi+cosphi)) =$

$(5cosphi)/(sinphi(sinphi+cosphi))=$

$(5 cotphi)/(sinphi+cosphi)$

How do you simplify (5cosphi)/sin^2phi*(sin^2phi-sinphicosphi)/(sin^2phi-cos^2phi)(5cosphi)/sin^2phi*(sin^2phi-sinphicosphi)/(sin^2phi-cos^2phi)?