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How do you simplify #(5b-4)1/5 #?

1 Answer

May 3, 2017

See the solution process below:

Explanation:

To simplify multiply each term within the parenthesis by the term outside the parenthesis:

#(5b - 4)color(red)(1/5) => (color(red)(1/5) * 5b) - (color(red)(1/5) * 4)#

#(color(red)(1/color(black)(cancel(color(red)(5)))) * color(red)(cancel(color(black)(5)))b) - 4/5 => 1b - 4/5 =>#

#b - 4/5#

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