How do you simplify #-5*sqrt3*4sqrt6#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Jul 7, 2015 #=color(blue)(-60) sqrt(2)# Explanation: #(-5.sqrt3). (4.sqrt6)# #=color(blue)((-5. 4))(sqrt3 . sqrt6)# #=color(blue)(-20) . (sqrt(3.6))# #=color(blue)(-20) . (sqrt(18))# #=color(blue)(-20) . (sqrt(3.3.2))# #=color(blue)(-20) . 3(sqrt(2))# #=color(blue)(-60) sqrt(2)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1201 views around the world You can reuse this answer Creative Commons License