How do you simplify #(5+sqrt3)(4-2sqrt 3)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Shwetank Mauria Sep 15, 2016 #(5+sqrt3)(4-2sqrt 3)=14-6sqrt3# Explanation: #(5+sqrt3)(4-2sqrt 3)# = #5(4-2sqrt 3)+sqrt3(4-2sqrt 3)# = #20-5xx2sqrt3+sqrt3xx4-sqrt3xx2sqrt3# = #20-10sqrt3+4sqrt3-2xx(sqrt3)^2# = #20-6sqrt3-2xx3# = #20--6sqrt3-6# = #14-6sqrt3# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 915 views around the world You can reuse this answer Creative Commons License