How do you simplify $(5 + \sqrt{3}) (4 - 2 \sqrt{3})$ $(5+sqrt3)(4-2sqrt 3)$ ?

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Answer 1 · 2016-09-15T03:42:42

$(5 + \sqrt{3}) (4 - 2 \sqrt{3}) = 14 - 6 \sqrt{3}$ $(5+sqrt3)(4-2sqrt 3)=14-6sqrt3$

$(5 + \sqrt{3}) (4 - 2 \sqrt{3})$ $(5+sqrt3)(4-2sqrt 3)$

= $5 (4 - 2 \sqrt{3}) + \sqrt{3} (4 - 2 \sqrt{3})$ $5(4-2sqrt 3)+sqrt3(4-2sqrt 3)$

= $20 - 5 \times 2 \sqrt{3} + \sqrt{3} \times 4 - \sqrt{3} \times 2 \sqrt{3}$ $20-5xx2sqrt3+sqrt3xx4-sqrt3xx2sqrt3$

= $20 - 10 \sqrt{3} + 4 \sqrt{3} - 2 \times {(\sqrt{3})}^{2}$ $20-10sqrt3+4sqrt3-2xx(sqrt3)^2$

= $20 - 6 \sqrt{3} - 2 \times 3$ $20-6sqrt3-2xx3$

= $20 - - 6 \sqrt{3} - 6$ $20--6sqrt3-6$

= $14 - 6 \sqrt{3}$ $14-6sqrt3$

How do you simplify (5+sqrt3)(4-2sqrt 3)(5+√3)(4−2√3)(5+sqrt3)(4-2sqrt 3)?