How do you simplify #5/(sqrt[3] + sqrt[5])#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Harish Chandra Rajpoot Jul 2, 2018 #\frac{5}{2}(\sqrt5-\sqrt3)# Explanation: #\frac{5}{\sqrt3+\sqrt5}# #=\frac{5}{\sqrt5+\sqrt3}# #=\frac{5(\sqrt5-\sqrt3)}{(\sqrt5+\sqrt3)(\sqrt5-\sqrt3)}# #=\frac{5(\sqrt5-\sqrt3)}{(\sqrt5)^2-(\sqrt3)^2}# #=\frac{5(\sqrt5-\sqrt3)}{5-3}# #=\frac{5}{2}(\sqrt5-\sqrt3)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1070 views around the world You can reuse this answer Creative Commons License