How do you simplify $\frac{5}{\sqrt{3} + \sqrt{5}}$ $5/(sqrt[3] + sqrt[5])$ ?

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Answer 1 · 2018-07-02T13:08:30

$\frac{5}{2} (\sqrt{5} - \sqrt{3})$ $\frac{5}{2}(\sqrt5-\sqrt3)$

$\frac{5}{\sqrt{3} + \sqrt{5}}$ $\frac{5}{\sqrt3+\sqrt5}$

$= \frac{5}{\sqrt{5} + \sqrt{3}}$ $=\frac{5}{\sqrt5+\sqrt3}$

$= \frac{5 (\sqrt{5} - \sqrt{3})}{(\sqrt{5} + \sqrt{3}) (\sqrt{5} - \sqrt{3})}$ $=\frac{5(\sqrt5-\sqrt3)}{(\sqrt5+\sqrt3)(\sqrt5-\sqrt3)}$

$= \frac{5 (\sqrt{5} - \sqrt{3})}{{(\sqrt{5})}^{2} - {(\sqrt{3})}^{2}}$ $=\frac{5(\sqrt5-\sqrt3)}{(\sqrt5)^2-(\sqrt3)^2}$

$= \frac{5 (\sqrt{5} - \sqrt{3})}{5 - 3}$ $=\frac{5(\sqrt5-\sqrt3)}{5-3}$

$= \frac{5}{2} (\sqrt{5} - \sqrt{3})$ $=\frac{5}{2}(\sqrt5-\sqrt3)$

How do you simplify 5/(sqrt[3] + sqrt[5])5√3+√55/(sqrt[3] + sqrt[5])?