How do you simplify #(5 sqrt 2 + sqrt 3)(sqrt 2 + 2 sqrt 3)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Marko T. May 16, 2018 #16+11sqrt6# Explanation: #(5sqrt2+sqrt3)*(sqrt2+2sqrt3)=# #(5sqrt2*sqrt2+5sqrt2*2sqrt3+sqrt3*sqrt2+sqrt3*2sqrt3)=# #(5*2+10sqrt6+sqrt6+2*3)=# #(10+11sqrt6+6)=# #16+11sqrt6# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 3806 views around the world You can reuse this answer Creative Commons License