How do you simplify #5 sqrt (1/3125)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Acquaintance Jul 7, 2016 #1/5# Explanation: #root(x)(a/b) = (rootxa)/(rootxb)# #root5 (1/3125) = root5 1/root5 3125# #= 1/5# Check work: #(1*1*1*1*1)/(5*5*5*5*5)# #1/(3125)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1408 views around the world You can reuse this answer Creative Commons License