How do you simplify #(5 - 8y)^2#?

1 Answer
Jim G.
Apr 27, 2017

#64y^2-80y+25#

Explanation:

Each term in the second bracket is multiplied by each term in the first bracket as shown below.

#(5-8y)^2=(5-8y)(5-8y)#

#rArr(color(red)(5-8y))(5-8y)#

#=color(red)(5)(5-8y)color(red)(-8y)(5-8y)#

#=(color(red)(5)xx5)+(color(red)(5)xx-8y)+(color(red)(-8y)xx5)+(color(red)(-8y)xx-8y)#

#=25+(-40y)+(-40y)+64y^2#

#=25-40y-40y+64y^2#

#=64y^2-80y+25larrcolor(red)" in standard form"#

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