How do you simplify $(4x-1)/(3x) + (x-8)/(5x)$ ?

Question

1917 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-14T05:15:49

The answer is $(23x-29)/(15x)$ .

$(4x-1)/(3x)+(x-8)/(5x)$

The LCD is $15$ . Multiply each fraction so that its denominator will be $15x$ .

$(4x-1)/(3x)xx5/5+(x-8)/(5x)xx3/3=$

$(5(4x-1))/(5(3x))+(3(x-8))/(3(5x)=$

Distribute the $5$ and the $3$ in the numerators and simplify $5*3x$ to $15x$ and $3*5x$ to $15x$ .

$(20x-5)/(15x)+(3x-24)/(15x)$

Combine the numerators over the denominator $15x$ .

$(20x-5+3x-24)/(15x)$

Combine like terms.

$(20x+3x-5-24)/(15x)=$

$(23x-29)/(15x)$

How do you simplify (4x-1)/(3x) + (x-8)/(5x)(4x-1)/(3x) + (x-8)/(5x)?