How do you simplify $(4 \sqrt{3} - 5 \sqrt{2}) \cdot (2 \sqrt{3} + 3 \sqrt{2})$ $(4sqrt3 - 5sqrt2 ) * (2sqrt3 + 3sqrt2)$ ?

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How do you simplify $(4 \sqrt{3} - 5 \sqrt{2}) \cdot (2 \sqrt{3} + 3 \sqrt{2})$ $(4sqrt3 - 5sqrt2 ) * (2sqrt3 + 3sqrt2)$ ?

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Answer 1 · 2015-04-02T17:35:33

$(4 \sqrt{3} - 5 \sqrt{2}) \cdot (2 \sqrt{3} + 3 \sqrt{2}) =$ $(4sqrt(3) - 5sqrt(2)) * (2sqrt(3) + 3sqrt(2)) =$

$4 \sqrt{3} \cdot 2 \sqrt{3} + 4 \sqrt{3} \cdot 3 \sqrt{2} - 5 \sqrt{2} \cdot 2 \sqrt{3} - 5 \sqrt{2} \cdot 3 \sqrt{2} =$ $4sqrt(3) * 2sqrt(3) + 4sqrt(3) * 3sqrt(2) -5sqrt(2) * 2sqrt(3) -5sqrt(2) * 3sqrt(2) =$

$8 \sqrt{3 \cdot 3} + 12 \sqrt{3 \cdot 2} - 10 \sqrt{2 \cdot 3} - 15 \sqrt{2 \cdot 2} =$ $8sqrt(3*3) +12sqrt(3*2) -10sqrt(2*3) -15sqrt(2*2) =$

$8 \sqrt{3^{2}} + 12 \sqrt{6} - 10 \sqrt{6} - 15 \sqrt{2^{2}} =$ $8sqrt(3^2) + 12sqrt(6) - 10sqrt(6) - 15sqrt(2^2) =$

$8 \cdot 3 + 12 \sqrt{6} - 10 \sqrt{6} - 15 \cdot 2 =$ $8*3 + 12sqrt(6) - 10sqrt(6) - 15*2 =$

$24 + \sqrt{6} \cdot (12 - 10) - 30 =$ $24 + sqrt(6) * (12 - 10) - 30 =$

Answer: $2 \sqrt{6} - 6$ $2sqrt(6) - 6$

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How do you simplify $(4 \sqrt{3} - 5 \sqrt{2}) \cdot (2 \sqrt{3} + 3 \sqrt{2})$ $(4sqrt3 - 5sqrt2 ) * (2sqrt3 + 3sqrt2)$ ?

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How do you simplify (4√3−5√2)⋅(2√3+3√2)(4sqrt3 - 5sqrt2 ) * (2sqrt3 + 3sqrt2)?

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How do you simplify $(4 \sqrt{3} - 5 \sqrt{2}) \cdot (2 \sqrt{3} + 3 \sqrt{2})$ $(4sqrt3 - 5sqrt2 ) * (2sqrt3 + 3sqrt2)$ ?