How do you simplify #4sqrt2(3/16) * sqrt1(2/5)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer hev1 Apr 6, 2018 #4sqrt(2)(3/16) * 1(2/5)# #=(4sqrt(2)*3)/16*2/5# #=(12sqrt(2))/16*2/5# #=(3sqrt(2))/4*2/5# #=(6sqrt(2))/20# #=(3sqrt(2))/10# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1358 views around the world You can reuse this answer Creative Commons License