How do you simplify #4sqrt11(2sqrt11+3sqrt5)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer MeneerNask Jul 13, 2015 First get rid of the brackets Explanation: #=4sqrt11*2sqrt11+4sqrt11*3sqrt5# #=4*2*(sqrt11)^2+4*3*sqrt(5*11)# #=8*11+12*sqrt55=88+12sqrt55# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1269 views around the world You can reuse this answer Creative Commons License