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How do you simplify #(4r^0)^4#?

1 Answer

Jun 15, 2015

#=color(blue)(256# ( assuming #r != 0)#

Explanation:

#(4r^0)^color(blue)(4#
Here, we need to multiply #color(blue)(4)# with the power of each term within the bracket.

#=4^color(blue)4 .r^(0. color(blue)(4)#

#=256.r^0#

#=256. 1# ------------- As (any non-zero number)#^0 = 1#

#=color(blue)(256#

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