How do you simplify 4div( sqrt3 + sqrt2)4÷(√3+√2)?

1 Answer
Gió
Sep 23, 2015

I found: 4(sqrt(3)-sqrt(2))4(√3−√2)

Explanation:

I think you can Rationalize (to get rid of roots in the denominator) multiplying and dividing by sqrt(3)-sqrt(2)√3−√2 and get:

4/(sqrt(3)+sqrt(2))*(sqrt(3)-sqrt(2))/(sqrt(3)-sqrt(2))=4(sqrt(3)-sqrt(2))/(3-2)=4√3+√2⋅√3−√2√3−√2=4√3−√23−2=
=4(sqrt(3)-sqrt(2))=4(√3−√2)

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