How do you simplify #4(z+2)#?
1 Answer
Dec 19, 2016
Explanation:
Each term inside the bracket must be multiplied by 4. This is known as the
#color(blue)"distributive law"#
#rArrcolor(red)(4)(z+2)#
#=(color(red)(4)xxz)+(color(red)(4)xx2)=4z+8#
